The sum of the first nth term of a geometric series is 145 ... -...
The sum of the first nth term of a geometric series is 145 and the sum of the reciprocal is 145/33. The first term is 1. What is n and the common ratio? Precalculus
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The sum of the first nth term of a geometric series is 145 and the sum of the reciprocal is 145/33. The first term is 1. What is n and the common ratio? Precalculus
First, subtract #color (red) ($145)# from each side of the equation to isolate the #w# term while keeping the equation balanced:
Feb 2, 2017 · Explanation: To eliminate the fractions in the equation, multiply ALL terms on both sides by the #color (blue)"lowest common multiple"# (LCM) of 5 ,14 and 7, the values on the denominators.
196 ft.^2 Refer to figures below From the given data we have D_1=6 ft. => r_1=3ft. D_2=4 fl. => r_2=2ft. h=12ft. As we can see in Fig. (a) r_2/(H-h)=r_1/H 2/(H-12)=3/H => 2H=3H-36 => H=36 Since s=sqrt(2)*r (see Fig.(b...
What we're really doing here is that we're given an initial state with # ["BrCl"]_i = "0.050 M"#, and we're given #K_ (eq)#, which is defined for a final state we define as equilibrium, when the rate of the forward re...
Maria had 105 beads to start with. First define the number of beads each girl had using variables. Let the number of beads that Maria had be x Together they had 250, so the number of beads that Farida had is 250-x Mar...
12.04 (approx) Let the length of side A or B = x and base is 16. So the height is sqrt [x^2 - (16/2)^2] Now the area of triangle = 1/2 * base * height = 1/2 * 16 * sqrt [x^2 - (16/2)^2]. Therefore, 1/2 * 16 * sqrt [x^...
No real solutions. Calling alpha = 4x+y we have { (sqrtx (1-alpha)=2), (sqrty (1+alpha)=6):} then 2 alpha = (1+alpha)^2- (1-alpha)^2=36/y-4/x or 4x+y = 9/y-1/x we ...
Jun 14, 2016 · The length of side A is 10.145 (3dp) The angle between sides A and B is /_c= pi/8=180/8=22.5^0 The angle between sides B and C is /_a= pi/12=180/12=15^0 Given C=15; A=?.
Aug 26, 2017 · Just Q8. I'll ask more questions if I need more help.