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It has been proved that ∠AOB = 90∘ if XY and X′Y' are two parallel tangents to a circle with center O and another tangent AB with the point of contact C intersecting XY at A and X′Y′ at B.
Ex 10.2,9 In figure, XY and X′Y′ are two parallel tangents to a circle with centre O and another tangent AB with point of contact C intersecting XY at A and X′Y′at B. Prove that ∠AOB = 90°.
Step by step video & image solution for In Fig XY and X'Y' are two parallel tangents to a circle with centre O and another tangent AB with point of contact C intersecting XY and X'Y' at B , prove that angle AOB = 90^@...
As we know that XY and X'Y' are parallel. So, here AB acts as a transversal. In order to prove the congruence you need to look at all the sides and angles which are equal because neglecting one of them changes the rul...
In the given figure, XY and X’Y’ are two parallel tangents to a circle with centre O and another tangent AB with point of contact C intersecting XY at A and X’Y’ at B. Prove that ∠AOB = 90°
Q) In Figure, XY and X′Y′ are two parallel tangents to a circle with centre O and another tangent AB with point of contact C intersecting XY at A and X′Y′ at B. Prove that ∠ AOB = 90°
In Figure 10.13, XY and X′ Y′ are two parallel tangents to a circle with centre O and another tangent AB with the point of contact C intersecting XY at A and X′ Y′ at B. Prove that ∠AOB = 90° (without construction)
